What is the solution for y^{''}+6y^'+9y=0,y(0)=2,y^'(0)=3 ?

The solution for y^{''}+6y^'+9y=0,y(0)=2,y^'(0)=3 is y=2e^{-3t}+9te^{-3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+6y^'+9y=0,y(0)=2,y^'(0)=3

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 3

y = 2 e^{- 3 t} + 9 t e^{- 3 t}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 2 e^{- 3 t} + 9 t e^{- 3 t}

y = 2 e^{- 3 t} + 9 t e^{- 3 t}

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (\frac{π}{2}) = 0, y^{^{'}} (\frac{π}{2}) = 9

y^{^{''}} - 6 y^{^{'}} + 14 y = 0

y^{^{''}} - y^{^{'}} + 6 y = 0

x^{^{''}} + a^{2} x = 0

y^{^{''}} - 14 y^{^{'}} + 40 y = 0

What is the solution for y^{''}+6y^'+9y=0,y(0)=2,y^'(0)=3 ?
The solution for y^{''}+6y^'+9y=0,y(0)=2,y^'(0)=3 is y=2e^{-3t}+9te^{-3t}