What is the solution for (d^2y)/(dx^2)-4(dy)/(dx)+13y=0 ?

The solution for (d^2y)/(dx^2)-4(dy)/(dx)+13y=0 is y=e^{2x}(c_{1}cos(3x)+c_{2}sin(3x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-4(dy)/(dx)+13y=0

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 13 y = 0

y = e^{2 x} (c_{1} cos (3 x) + c_{2} sin (3 x))

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 13 y = 0

Solve linear ODE:

y = e^{2 x} (c_{1} cos (3 x) + c_{2} sin (3 x))

y = e^{2 x} (c_{1} cos (3 x) + c_{2} sin (3 x))

y^{^{''}} - y^{^{'}} - 20 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + 12 y^{^{'}} + 35 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = 11, y^{^{'}} (0) = 28

7 y^{^{''}} + 13 y^{^{'}} - 2 y = 0

25 y^{^{''}} - 40 y^{^{'}} + 16 y = 0, y (0) = 2, y^{^{'}} (0) = 3

What is the solution for (d^2y)/(dx^2)-4(dy)/(dx)+13y=0 ?
The solution for (d^2y)/(dx^2)-4(dy)/(dx)+13y=0 is y=e^{2x}(c_{1}cos(3x)+c_{2}sin(3x))