What is the integral of (2sec^2(x)-5cos(x)) ?

The integral of (2sec^2(x)-5cos(x)) is 2tan(x)-5sin(x)+C

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integral of (2sec^2(x)-5cos(x))

\int (2 sec^{2} (x) - 5 cos (x)) d x

2 tan (x) - 5 sin (x) + C

Solution steps

\int 2 sec^{2} (x) - 5 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 sec^{2} (x) d x - \int 5 cos (x) d x

\int 2 sec^{2} (x) d x = 2 tan (x)

\int 5 cos (x) d x = 5 sin (x)

= 2 tan (x) - 5 sin (x)

Add a constant to the solution

= 2 tan (x) - 5 sin (x) + C

lo g_{10} (x + 1)

y^{^{''}} + 4 y^{^{'}} + 4 y = t - 2 e - 2 t

x \to 2 lim (\frac{1}{x + 2})

\int sin (x) - cos (x) + 4 d x

\int (e^{x} sin (y) + tan (y)) d x

What is the integral of (2sec^2(x)-5cos(x)) ?
The integral of (2sec^2(x)-5cos(x)) is 2tan(x)-5sin(x)+C