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Popular >

y^{''}-25y^'=0

Solution

y^{^{''}} - 25 y^{^{'}} = 0

Solution

y = c_{1} e^{25 t} + c_{2}

Solution steps

y^{''} (t) - 25 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} e^{25 t} + c_{2}

y = c_{1} e^{25 t} + c_{2}

Graph

Popular Examples

y^{''}+y^'=0,y(pi/2)=2,y^'(pi/2)=1

y^{^{''}} + y^{^{'}} = 0, y (\frac{π}{2}) = 2, y^{^{'}} (\frac{π}{2}) = 1

(d^2y)/(dx^2)+4(dy)/(dx)=0

\frac{d ^{2} y}{d x ^{2}} + 4 \frac{d y}{d x} = 0

(d^2y)/(dx^2)+3(dy)/(dx)-10y=0

\frac{d ^{2} y}{d x ^{2}} + 3 \frac{d y}{d x} - 10 y = 0

x^{^{''}} = 2 x

y^{''}-3y^'-4y=0,y(0)=1,y^'(0)=2

y^{^{''}} - 3 y^{^{'}} - 4 y = 0, y (0) = 1, y^{^{'}} (0) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-25y^'=0 ?
The solution for y^{''}-25y^'=0 is y=c_{1}e^{25t}+c_{2}