What is u^{'''}+u^{''}-2\H(t)=0 ?

The answer to u^{'''}+u^{''}-2\H(t)=0 is 0+0-2\H(t(x))=0

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u^{'''}+u^{''}-2\H(t)=0

u^{'''} + u^{''} - 2 H (t (x)) = 0

0 + 0 - 2 H (t (x)) = 0

Solution steps

u^{'''} + u^{''} - 2 H (t (x)) = 0

u^{'''} = 0

0 + u^{^{''}} - 2 H (t (x)) = 0

u^{''} = 0

0 + 0 - 2 H (t (x)) = 0

16 y^{^{''}} - 8 y^{^{'}} + 145 y = 0

y^{^{''}} + 16 y = 0

y^{^{''''}} - 2 y^{^{'''}} - 3 y^{^{''}} + 4 y^{^{'}} + 4 y = 0

y^{^{''''}} - 23 y^{^{''}} - 50 y = 0

y^{^{''}} + 5 y^{^{'}} + 4 y = 0, y (0) = 6, y^{^{'}} (0) = 2

What is u^{'''}+u^{''}-2\H(t)=0 ?
The answer to u^{'''}+u^{''}-2\H(t)=0 is 0+0-2\H(t(x))=0