What is the solution for y^{''}+y^'-y=0,y(-4)=7,y^'(-4)=1 ?

The solution for y^{''}+y^'-y=0,y(-4)=7,y^'(-4)=1 is

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y^{''}+y^'-y=0,y(-4)=7,y^'(-4)=1

y^{^{''}} + y^{^{'}} - y = 0, y (- 4) = 7, y^{^{'}} (- 4) = 1

y = 7 e^{2 (5 - 1)} - \frac{e ^{45} ( 7 5 e ^{2 (- 1 - 5)} - 9 e ^{2 (- 1 - 5)} )}{2 5} e^{\frac{( - 1 + 5 ) t}{2}} + \frac{7 5 e ^{2 (- 1 - 5)} - 9 e ^{2 (- 1 - 5)}}{2 5} e^{\frac{( - 1 - 5 ) t}{2}}

Solution steps

y^{''} (t) + y^{'} (t) - y = 0

Solve linear ODE:

y = 7 e^{2 (5 - 1)} - \frac{e ^{45} ( 7 5 e ^{2 (- 1 - 5)} - 9 e ^{2 (- 1 - 5)} )}{2 5} e^{\frac{( - 1 + 5 ) t}{2}} + \frac{7 5 e ^{2 (- 1 - 5)} - 9 e ^{2 (- 1 - 5)}}{2 5} e^{\frac{( - 1 - 5 ) t}{2}}

y = 7 e^{2 (5 - 1)} - \frac{e ^{45} ( 7 5 e ^{2 (- 1 - 5)} - 9 e ^{2 (- 1 - 5)} )}{2 5} e^{\frac{( - 1 + 5 ) t}{2}} + \frac{7 5 e ^{2 (- 1 - 5)} - 9 e ^{2 (- 1 - 5)}}{2 5} e^{\frac{( - 1 - 5 ) t}{2}}

y^{^{''''}} - 3 y^{^{'''}} + 3 y^{^{''}} - y^{^{'}} = 0

y^{^{''''''''}} + 8 y^{^{''''}} + 16 y = 0

y^{^{''}} + y = 0, y (\frac{π}{3}) = 6, y^{^{'}} (\frac{π}{3}) = - 12

4 y^{^{''}} + 17 y^{^{'}} + 4 y = 0

y^{^{''''}} - 18 y^{^{'''}} + 81 y^{^{''}} = 0

What is the solution for y^{''}+y^'-y=0,y(-4)=7,y^'(-4)=1 ?
The solution for y^{''}+y^'-y=0,y(-4)=7,y^'(-4)=1 is