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Popular >

4y^{''}+36y=0

Solution

4 y^{^{''}} + 36 y = 0

Solution

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Solution steps

4 y^{''} (t) + 36 y = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Graph

Popular Examples

36y^{'''}+60y^{''}+25y^'=0

36 y^{^{'''}} + 60 y^{^{''}} + 25 y^{^{'}} = 0

h^{''}-2h^'+10h=0,h(0)=1,h^'(0)=10

h^{^{''}} - 2 h^{^{'}} + 10 h = 0, h (0) = 1, h^{^{'}} (0) = 10

y^{''}-y=0,y(0)=2,y^'(0)=-1

y^{^{''}} - y = 0, y (0) = 2, y^{^{'}} (0) = - 1

y^{''}+y=0,y(pi/2)=0,y(0)=1

y^{^{''}} + y = 0, y (\frac{π}{2}) = 0, y (0) = 1

(d^3y)/(dx^3)+(d^2y)/(dx^2)=0

\frac{d ^{3} y}{d x ^{3}} + \frac{d ^{2} y}{d x ^{2}} = 0

Frequently Asked Questions (FAQ)

What is the solution for 4y^{''}+36y=0 ?
The solution for 4y^{''}+36y=0 is y=c_{1}cos(3t)+c_{2}sin(3t)