What is (\partial)/(\partial x)(48x^7y^7+30x^5y^5) ?

The answer to (\partial)/(\partial x)(48x^7y^7+30x^5y^5) is 336y^7x^6+150y^5x^4

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(\partial)/(\partial x)(48x^7y^7+30x^5y^5)

\frac{\partial}{\partial x} (48 x^{7} y^{7} + 30 x^{5} y^{5})

336 y^{7} x^{6} + 150 y^{5} x^{4}

Solution steps

\frac{\partial}{\partial x} (48 x^{7} y^{7} + 30 x^{5} y^{5})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (48 x^{7} y^{7}) + \frac{\partial}{\partial x} (30 x^{5} y^{5})

\frac{\partial}{\partial x} (48 x^{7} y^{7}) = 336 y^{7} x^{6}

\frac{\partial}{\partial x} (30 x^{5} y^{5}) = 150 y^{5} x^{4}

= 336 y^{7} x^{6} + 150 y^{5} x^{4}

\frac{d}{d x} (- 3 7 x - 1)

\int o d o

f (t) = 1 + ln (t)

2 y y^{^{'}} + 2 = y^{2} + 2 x, y (0) = 8

\frac{\partial}{\partial v} (3 v sin (u))

What is (\partial)/(\partial x)(48x^7y^7+30x^5y^5) ?
The answer to (\partial)/(\partial x)(48x^7y^7+30x^5y^5) is 336y^7x^6+150y^5x^4