What is inverse oflaplace 2/(s^5) ?

The answer to inverse oflaplace 2/(s^5) is (t^4)/(12)

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inverse oflaplace 2/(s^5)

inverse laplace

\frac{2}{s ^{5}}

\frac{t ^{4}}{12}

Solution steps

L^{- 1} {\frac{2}{s ^{5}}}

= L^{- 1} {\frac{1}{12} \cdot \frac{24}{s ^{5}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{12} L^{- 1} {\frac{24}{s ^{5}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{24}{s ^{5}}} = t^{4}

= \frac{1}{12} t^{4}

= \frac{t ^{4}}{12}

x \to 0 lim (sin (x^{12}))

\frac{d}{d x} (x arcsec (x^{3}))

\frac{( 6 + 6 s )}{2 s ^{2} + 1}

x \to 1 + lim (\frac{x - 3}{x - 1})

9 x^{\frac{1}{2}}

What is inverse oflaplace 2/(s^5) ?
The answer to inverse oflaplace 2/(s^5) is (t^4)/(12)