Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+8y^'+16y=0,y(0)=1,y^'(0)=-2y^{''}+16y^'+ay=0,y(0)=1,y^'(0)=-12y^{''}+3y^'+7y=0y^{''}+y^'=yy^{'''}+2y^{''}-19y^'-20y=0
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+y^'-2y=0,y(0)=e^t ?
The solution for y^{''}+y^'-2y=0,y(0)=e^t is y=c_{1}e^t+c_{2}e^{-2t}