What is the solution for (d^2y)/(dx^2)-6(dy)/(dx)+14y=0 ?

The solution for (d^2y)/(dx^2)-6(dy)/(dx)+14y=0 is y=e^{3x}(c_{1}cos(sqrt(5)x)+c_{2}sin(sqrt(5)x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-6(dy)/(dx)+14y=0

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 14 y = 0

y = e^{3 x} (c_{1} cos (5 x) + c_{2} sin (5 x))

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 14 y = 0

Solve linear ODE:

y = e^{3 x} (c_{1} cos (5 x) + c_{2} sin (5 x))

y = e^{3 x} (c_{1} cos (5 x) + c_{2} sin (5 x))

y^{^{''}} - 13 y^{^{'}} + 30 y = 0

y^{^{'''}} - 5 y^{^{''}} - y^{^{'}} + 5 y = 0

2 y^{^{''}} + 5 y^{^{'}} - 3 y = 0, y (0) = - 1, y^{^{'}} (0) = 17

y^{^{'''}} - 3 y^{^{''}} - 25 y^{^{'}} - 21 y = 0

0.5 y^{^{''}} + 6 y^{^{'}} + 50 y = 0

What is the solution for (d^2y)/(dx^2)-6(dy)/(dx)+14y=0 ?
The solution for (d^2y)/(dx^2)-6(dy)/(dx)+14y=0 is y=e^{3x}(c_{1}cos(sqrt(5)x)+c_{2}sin(sqrt(5)x))