What is the solution for y^{'''}+9y^{''}=0 ?

The solution for y^{'''}+9y^{''}=0 is y=c_{1}e^{-9t}+c_{2}+c_{3}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}+9y^{''}=0

y^{^{'''}} + 9 y^{^{''}} = 0

y = c_{1} e^{- 9 t} + c_{2} + c_{3} t

Solution steps

y^{'''} (t) + 9 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{- 9 t} + c_{2} + c_{3} t

y = c_{1} e^{- 9 t} + c_{2} + c_{3} t

y^{^{''}} + 36 y = 0, y (π) = 0, y (0) = 0

y^{^{'''}} - 8 y^{^{''}} = 0

y^{^{'''}} - y^{^{''}} - 56 y^{^{'}} = 0

y^{^{''}} + y = 0, y (\frac{π}{2}) = 0, y^{^{'}} (\frac{π}{2}) = 1

4 y^{^{''}} - 16 y^{^{'}} + 17 y = 0

What is the solution for y^{'''}+9y^{''}=0 ?
The solution for y^{'''}+9y^{''}=0 is y=c_{1}e^{-9t}+c_{2}+c_{3}t