What is the solution for y^{''}+49y=0,y(0)=5,y^'(0)=-7 ?

The solution for y^{''}+49y=0,y(0)=5,y^'(0)=-7 is y=5cos(7t)-sin(7t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+49y=0,y(0)=5,y^'(0)=-7

y^{^{''}} + 49 y = 0, y (0) = 5, y^{^{'}} (0) = - 7

y = 5 cos (7 t) - sin (7 t)

Solution steps

y^{''} (t) + 49 y = 0

Solve linear ODE:

y = 5 cos (7 t) - sin (7 t)

y = 5 cos (7 t) - sin (7 t)

y^{^{''}} + y = 0, y (π) = 0, y (0) = 0

y^{^{''}} - 13 y^{^{'}} + 42 y = 0

x^{^{''}} + 2 \cdot x^{^{'}} + 10 x = 0

y^{^{''}} - 121 y = 0

y^{^{''}} + 9 y = 0, y (0) = 1, y^{^{'}} (0) = 1

What is the solution for y^{''}+49y=0,y(0)=5,y^'(0)=-7 ?
The solution for y^{''}+49y=0,y(0)=5,y^'(0)=-7 is y=5cos(7t)-sin(7t)