What is the integral of sqrt(x-3) ?

The integral of sqrt(x-3) is 2/3 (x-3)^{3/2}+C

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integral of sqrt(x-3)

\int x - 3 d x

\frac{2}{3} (x - 3)^{\frac{3}{2}} + C

Solution steps

\int x - 3 d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x - 3

= \frac{2}{3} (x - 3)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (x - 3)^{\frac{3}{2}} + C

\int (7 - \frac{1}{x ^{6}})^{2} (\frac{1}{x ^{7}}) d x

f (t) = e^{t} - 1

\frac{d}{d x} (3 x - x)

f (x) = \frac{ln ( x )}{x ^{4}}

y = 2 sin (x) + sin (2 x), x = 0, x = π

What is the integral of sqrt(x-3) ?
The integral of sqrt(x-3) is 2/3 (x-3)^{3/2}+C