en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y=0

Solution

y^{^{''}} + 4 y = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

y^{''} (t) + 4 y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Graph

Popular Examples

y^{''}+40y^'+6250y=0

y^{^{''}} + 40 y^{^{'}} + 6250 y = 0

y^{''}+4y=0,y(0)=0,y^'(0)=2

y^{^{''}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 2

y^{''}+4y=0,y(0)=0,y^'(0)=3

y^{^{''}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 3

y^{''}+2y^'+7y=0

y^{^{''}} + 2 y^{^{'}} + 7 y = 0

y^{''}-2y=0,y(0)=1,y^'(0)=2

y^{^{''}} - 2 y = 0, y (0) = 1, y^{^{'}} (0) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y=0 ?
The solution for y^{''}+4y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)