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Popular >

y^{''}+144y=0

Solution

y^{^{''}} + 144 y = 0

Solution

y = c_{1} cos (12 t) + c_{2} sin (12 t)

Solution steps

y^{''} (t) + 144 y = 0

Solve linear ODE:

y = c_{1} cos (12 t) + c_{2} sin (12 t)

y = c_{1} cos (12 t) + c_{2} sin (12 t)

Graph

Popular Examples

5/8 x^{''}+40x=0

\frac{5}{8} x^{^{''}} + 40 x = 0

y^{''}-12y^'+36y=0,y(0)=4,y^'(0)=15.451

y^{^{''}} - 12 y^{^{'}} + 36 y = 0, y (0) = 4, y^{^{'}} (0) = 15.451

(d^2y)/(dt^2)-4(dy)/(dt)=0

\frac{d ^{2} y}{d t ^{2}} - 4 \frac{d y}{d t} = 0

y^{''}+18y^'=0,y(0)=18

y^{^{''}} + 18 y^{^{'}} = 0, y (0) = 18

(d^2f)/(dx^2)=f(x)

\frac{d ^{2} f}{d x ^{2}} = f (x)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+144y=0 ?
The solution for y^{''}+144y=0 is y=c_{1}cos(12t)+c_{2}sin(12t)