Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
2y^{''}+2y^'+y=0,y(0)=1,y^'(0)=2y^{''''}-a^4y=0u^{''}-a^2\H(t)=0y^{''}-y=0,y^1(0)=cosh(x)y^{'''}+5y^{''}-y^'-5y=0
Frequently Asked Questions (FAQ)
What is the solution for 15y^{''}-16y^'+y=0,y(0)=15,y^'(0)= 1/15 ?
The solution for 15y^{''}-16y^'+y=0,y(0)=15,y^'(0)= 1/15 is y=-e^t+16e^{t/(15)}