en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+256y=0

Solution

y^{^{''}} + 256 y = 0

Solution

y = c_{1} cos (16 t) + c_{2} sin (16 t)

Solution steps

y^{''} (t) + 256 y = 0

Solve linear ODE:

y = c_{1} cos (16 t) + c_{2} sin (16 t)

y = c_{1} cos (16 t) + c_{2} sin (16 t)

Popular Examples

y^{''}+2y^'-3y=0,y(0)=1,y^'(0)=3

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 3

(d^3y)/(dx^3)+3(d^2y)/(dx^2)-4y=0

\frac{d ^{3} y}{d x ^{3}} + 3 \frac{d ^{2} y}{d x ^{2}} - 4 y = 0

y^{''}+ky^'+8y=0

y^{^{''}} + k y^{^{'}} + 8 y = 0

100y^{''}-140y^'+85y=0,y(2)=9,y^'(2)=8

100 y^{^{''}} - 140 y^{^{'}} + 85 y = 0, y (2) = 9, y^{^{'}} (2) = 8

x^{^{''}} - 6 x = 0

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+256y=0 ?
The solution for y^{''}+256y=0 is y=c_{1}cos(16t)+c_{2}sin(16t)