What is the solution for f^{''}(x)+f(x)=0 ?

The solution for f^{''}(x)+f(x)=0 is f(x)=c_{1}cos(x)+c_{2}sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f^{''}(x)+f(x)=0

f^{^{''}} (x) + f (x) = 0

f (x) = c_{1} cos (x) + c_{2} sin (x)

Solution steps

f^{''} (x) + f (x) = 0

Solve linear ODE:

f (x) = c_{1} cos (x) + c_{2} sin (x)

f (x) = c_{1} cos (x) + c_{2} sin (x)

x^{^{''}} + 14 x^{^{'}} + 49 x = 0

y^{^{''}} + 4 y = 0, y^{^{'}} (π) = 0, y (0) = 0

x^{^{''}} - x^{^{'}} - 2 x = 0

y^{^{''}} - 3 y^{^{'}} - 10 y = 0, y (0) = 1

x^{^{''}} - 7 x^{^{'}} - 8 x = 0

What is the solution for f^{''}(x)+f(x)=0 ?
The solution for f^{''}(x)+f(x)=0 is f(x)=c_{1}cos(x)+c_{2}sin(x)