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Popular >

u^{''}+4u^'+4\H(t)=0

Solution

u^{''} + 4 u^{'} + 4 H (t (x)) = 0

Solution

0 + 4 \cdot 0 + 4 H (t (x)) = 0

Solution steps

u^{''} + 4 u^{'} + 4 H (t (x)) = 0

u^{''} = 0

0 + 4 u^{^{'}} + 4 H (t (x)) = 0

u^{'} = 0

0 + 4 \cdot 0 + 4 H (t (x)) = 0

Popular Examples

x^{^{''}} - 8 x = 0

(d^2y)/(dx^2)-4(dy)/(dx)-12y=0

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} - 12 y = 0

y^{''}-6y^'+13y=0,y(0)=1,y^'(0)=2

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (0) = 1, y^{^{'}} (0) = 2

(d^2+4d+20)^2y=0

(d^{2} + 4 d + 20)^{2} y = 0

y^{''}+y^'-2y=0,y(0)=6,y^'(0)=3

y^{^{''}} + y^{^{'}} - 2 y = 0, y (0) = 6, y^{^{'}} (0) = 3

Frequently Asked Questions (FAQ)

What is u^{''}+4u^'+4\H(t)=0 ?
The answer to u^{''}+4u^'+4\H(t)=0 is 0+4*0+4\H(t(x))=0