What is the solution for y^{''}+4y=0,y^'(0)=0,y(0)=0 ?

The solution for y^{''}+4y=0,y^'(0)=0,y(0)=0 is y=0

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y^{''}+4y=0,y^'(0)=0,y(0)=0

y^{^{''}} + 4 y = 0, y^{^{'}} (0) = 0, y (0) = 0

y = 0

Solution steps

y^{''} (t) + 4 y = 0

Solve linear ODE:

y = 0

y = 0

0.701 x^{^{''}} + 27.4667 x = 0

\frac{1}{8} x^{^{''}} + x^{^{'}} + 2 x = 0

2 y^{^{''}} - 3 y^{^{'}} - 2 y = 0, y (0) = 2, y^{^{'}} (0) = - \frac{7}{2}

10 x^{^{''}} + 30 x^{^{'}} + 20 x = 0

y^{^{''}} + \frac{5}{2} y^{^{'}} + y = 0

What is the solution for y^{''}+4y=0,y^'(0)=0,y(0)=0 ?
The solution for y^{''}+4y=0,y^'(0)=0,y(0)=0 is y=0