What is the solution for 3y^{''}-y^'=5y ?

The solution for 3y^{''}-y^'=5y is y=c_{1}e^{((1+sqrt(61))t)/6}+c_{2}e^{((1-sqrt(61))t)/6}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3y^{''}-y^'=5y

3 y^{^{''}} - y^{^{'}} = 5 y

y = c_{1} e^{\frac{( 1 + 61 ) t}{6}} + c_{2} e^{\frac{( 1 - 61 ) t}{6}}

Solution steps

3 y^{''} (t) - y^{'} (t) = 5 y

Solve linear ODE:

y = c_{1} e^{\frac{( 1 + 61 ) t}{6}} + c_{2} e^{\frac{( 1 - 61 ) t}{6}}

y = c_{1} e^{\frac{( 1 + 61 ) t}{6}} + c_{2} e^{\frac{( 1 - 61 ) t}{6}}

y^{^{''}} - y^{^{'}} - 42 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{''}} - y = 0, y (0) = 0, y^{^{'}} (0) = 5

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (π) = 1, y (0) = 1

\frac{1}{8} y^{^{''}} + y^{^{'}} + 2 y = 0, y (0) = - 1, y^{^{'}} (0) = 12

y^{^{''}} + 6 y^{^{'}} + 13 y = 0, y (0) = 2, y^{^{'}} (0) = - 5

What is the solution for 3y^{''}-y^'=5y ?
The solution for 3y^{''}-y^'=5y is y=c_{1}e^{((1+sqrt(61))t)/6}+c_{2}e^{((1-sqrt(61))t)/6}