What is the solution for x^{''}+5*x=0 ?

The solution for x^{''}+5*x=0 is x=c_{1}cos(sqrt(5)t)+c_{2}sin(sqrt(5)t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+5*x=0

x^{^{''}} + 5 \cdot x = 0

x = c_{1} cos (5 t) + c_{2} sin (5 t)

Solution steps

x^{''} (t) + 5 \cdot x = 0

Solve linear ODE:

x = c_{1} cos (5 t) + c_{2} sin (5 t)

x = c_{1} cos (5 t) + c_{2} sin (5 t)

y^{^{''}} + 121 y = 0

2 y^{^{''}} + 4 y^{^{'}} + 8 y = 0

2 y^{^{''}} - 3 y^{^{'}} + 1 y = 0

x^{^{''}} + 12 x^{^{'}} + 27 x = 0, x (0) = 1, x^{^{'}} (0) = 0

(4 D^{4} - 45 D^{2} - 70 D - 24) y = 0

What is the solution for x^{''}+5*x=0 ?
The solution for x^{''}+5*x=0 is x=c_{1}cos(sqrt(5)t)+c_{2}sin(sqrt(5)t)