What is the solution for y^{''}-18y^'+81y=0,y(0)=0,y^'(0)=5 ?

The solution for y^{''}-18y^'+81y=0,y(0)=0,y^'(0)=5 is y=5e^{9t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-18y^'+81y=0,y(0)=0,y^'(0)=5

y^{^{''}} - 18 y^{^{'}} + 81 y = 0, y (0) = 0, y^{^{'}} (0) = 5

y = 5 e^{9 t} t

Solution steps

y^{''} (t) - 18 y^{'} (t) + 81 y = 0

Solve linear ODE:

y = 5 e^{9 t} t

y = 5 e^{9 t} t

\frac{d ^{2} y}{d x ^{2}} - 13 \frac{d y}{d x} + 40 y = 0

(d^{2} - 2 d + 2) y = 0

y^{^{''}} + y^{^{'}} + 5 y = 0, y (0) = 1.2, y^{^{'}} (0) = 0

(x - 1) y^{^{''}} - x y + y = 0

3 \frac{d ^{2} y}{d x ^{2}} + 4 \frac{d y}{d x} + y = 0

What is the solution for y^{''}-18y^'+81y=0,y(0)=0,y^'(0)=5 ?
The solution for y^{''}-18y^'+81y=0,y(0)=0,y^'(0)=5 is y=5e^{9t}t