What is the solution for y^{''}+14y=0 ?

The solution for y^{''}+14y=0 is y=c_{1}cos(sqrt(14)t)+c_{2}sin(sqrt(14)t)

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y^{''}+14y=0

y^{^{''}} + 14 y = 0

y = c_{1} cos (14 t) + c_{2} sin (14 t)

Solution steps

y^{''} (t) + 14 y = 0

Solve linear ODE:

y = c_{1} cos (14 t) + c_{2} sin (14 t)

y = c_{1} cos (14 t) + c_{2} sin (14 t)

34 y + 10 y^{^{'}} + y^{^{''}} = 0, y (0) = - 3, y^{^{'}} (0) = 6

y^{^{''}} - 25 y = 0, y (0) = e^{5 x}

y^{^{''}} + 24 y = 0

6 y^{^{''}} - y^{^{'}} - 15 y = 0

y^{^{''}} + 3 y = 0, y (0) = \frac{π}{8}, y^{^{'}} (0) = 0

What is the solution for y^{''}+14y=0 ?
The solution for y^{''}+14y=0 is y=c_{1}cos(sqrt(14)t)+c_{2}sin(sqrt(14)t)