What is 1/8 u^{''}+4/5 u^'+28\H(t)=0 ?

The answer to 1/8 u^{''}+4/5 u^'+28\H(t)=0 is 1/8*0+4/5*0+28\H(t(x))=0

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1/8 u^{''}+4/5 u^'+28\H(t)=0

\frac{1}{8} u^{''} + \frac{4}{5} u^{'} + 28 H (t (x)) = 0

\frac{1}{8} \cdot 0 + \frac{4}{5} \cdot 0 + 28 H (t (x)) = 0

Solution steps

\frac{1}{8} u^{''} + \frac{4}{5} u^{'} + 28 H (t (x)) = 0

u^{''} = 0

\frac{1}{8} \cdot 0 + \frac{4}{5} u^{^{'}} + 28 H (t (x)) = 0

u^{'} = 0

\frac{1}{8} \cdot 0 + \frac{4}{5} \cdot 0 + 28 H (t (x)) = 0

y^{^{''}} + 10 y^{^{'}} + 15 y = 0

y^{^{''}} + 36 y = 0, y (0) = 4, y^{^{'}} (0) = 1

y^{^{'''}} + y^{^{''}} - 12 y^{^{'}} = 0

4 \frac{d ^{2} x}{d t ^{2}} + \frac{324}{4} x = 0

8 y^{^{''}} + 23 y^{^{'}} - 3 y = 0

What is 1/8 u^{''}+4/5 u^'+28\H(t)=0 ?
The answer to 1/8 u^{''}+4/5 u^'+28\H(t)=0 is 1/8*0+4/5*0+28\H(t(x))=0