What is the solution for y^{''}=5y,y^0=-2,y^2=10 ?

The solution for y^{''}=5y,y^0=-2,y^2=10 is y=c_{1}e^{sqrt(5)t}+c_{2}e^{-sqrt(5)t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}=5y,y^0=-2,y^2=10

y^{^{''}} = 5 y, y^{0} (0) = - 2, y^{2} (0) = 10

y = c_{1} e^{5 t} + c_{2} e^{- 5 t}

Solution steps

y^{''} (t) = 5 y

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{- 5 t}

y = c_{1} e^{5 t} + c_{2} e^{- 5 t}

y^{^{''}} + 4 a^{2} y^{^{'}} + y = 0

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = - 1, y^{^{'}} (0) = 3

\frac{d ^{4} y}{d t ^{4}} - y = 0

y^{^{''}} + 2 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''''}} - 8 y^{^{'}} = 0

What is the solution for y^{''}=5y,y^0=-2,y^2=10 ?
The solution for y^{''}=5y,y^0=-2,y^2=10 is y=c_{1}e^{sqrt(5)t}+c_{2}e^{-sqrt(5)t}