What is the solution for y^{''}-y^'-11y=0 ?

The solution for y^{''}-y^'-11y=0 is y=c_{1}e^{((1+3sqrt(5))t)/2}+c_{2}e^{((1-3sqrt(5))t)/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'-11y=0

y^{^{''}} - y^{^{'}} - 11 y = 0

y = c_{1} e^{\frac{( 1 + 3 5 ) t}{2}} + c_{2} e^{\frac{( 1 - 3 5 ) t}{2}}

Solution steps

y^{''} (t) - y^{'} (t) - 11 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( 1 + 3 5 ) t}{2}} + c_{2} e^{\frac{( 1 - 3 5 ) t}{2}}

y = c_{1} e^{\frac{( 1 + 3 5 ) t}{2}} + c_{2} e^{\frac{( 1 - 3 5 ) t}{2}}

y^{^{''}} + 2 y^{^{'}} + 5 y = 0, y (0) = 2, y (0) = 4

2 y^{^{''}} - 7 y^{^{'}} - 4 y = 0

y^{^{''}} - 2 y^{^{'}} + 24 y = 0

35 y^{^{''''}} + 153 y^{^{''}} + 100 y = 0

y^{^{''}} - 8 y^{^{'}} - 9 y = 0, y (0) = 0, y^{^{'}} (0) = 4

What is the solution for y^{''}-y^'-11y=0 ?
The solution for y^{''}-y^'-11y=0 is y=c_{1}e^{((1+3sqrt(5))t)/2}+c_{2}e^{((1-3sqrt(5))t)/2}