Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+2y^'+5y=0,y(0)=0,y^'(0)=0y^{''}+αy=0y^{''}-3y^'-40y=0,y(0)=-3,y^'(0)=4y^{''}+33y=0y^{''}-8y+16y=0
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+2y^'+5y=0,y(0)=0,y^'(0)=2 ?
The solution for y^{''}+2y^'+5y=0,y(0)=0,y^'(0)=2 is y=e^{-t}sin(2t)