What is the integral from-1 to 1 of 1/(x^2+1) ?

The integral from-1 to 1 of 1/(x^2+1) is pi/2

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integral from-1 to 1 of 1/(x^2+1)

\int_{- 1}^{1} \frac{1}{x ^{2} + 1} d x

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

\int_{- 1}^{1} \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= [arctan (x)]_{- 1}^{1}

Compute the boundaries:

\frac{π}{2}

= \frac{π}{2}

y^{^{''}} + 4 y = - 4 sec (2 t)

x^{^{''}} + 4 x^{^{'}} + 5 x = 0

\frac{\partial}{\partial n} (nm)

x \to 2 lim (\frac{3 x + 2}{x + 2})

\int_{0}^{2} (2 x + 2 - x^{2} - 2) d x

What is the integral from-1 to 1 of 1/(x^2+1) ?
The integral from-1 to 1 of 1/(x^2+1) is pi/2