What is the solution for y^{''}+3y^'+5y=0,y(0)=0 ?

The solution for y^{''}+3y^'+5y=0,y(0)=0 is y=c_{2}e^{-(3t)/2}sin((sqrt(11)t)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+3y^'+5y=0,y(0)=0

y^{^{''}} + 3 y^{^{'}} + 5 y = 0, y (0) = 0

y = c_{2} e^{- \frac{3 t}{2}} sin (\frac{11 t}{2})

Solution steps

y^{''} (t) + 3 y^{'} (t) + 5 y = 0

Solve linear ODE:

y = c_{2} e^{- \frac{3 t}{2}} sin (\frac{11 t}{2})

y = c_{2} e^{- \frac{3 t}{2}} sin (\frac{11 t}{2})

y^{^{''''}} + y^{^{''}} - 12 y = 0

y^{^{''''}} - 9 y^{^{'''}} + 19 y^{^{''}} + 29 y^{^{'}} = 0

y^{^{'''}} + 21 y^{^{''}} + 117 y^{^{'}} + 97 y = 0

36 y^{^{''}} - 60 y^{^{'}} + 25 y = 0

y^{^{''}} - 225 y = 0

What is the solution for y^{''}+3y^'+5y=0,y(0)=0 ?
The solution for y^{''}+3y^'+5y=0,y(0)=0 is y=c_{2}e^{-(3t)/2}sin((sqrt(11)t)/2)