What is the solution for 7y^{''}+y^'-y=0 ?

The solution for 7y^{''}+y^'-y=0 is y=c_{1}e^{((-1+sqrt(29))t)/(14)}+c_{2}e^{((-1-sqrt(29))t)/(14)}

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7y^{''}+y^'-y=0

7 y^{^{''}} + y^{^{'}} - y = 0

y = c_{1} e^{\frac{( - 1 + 29 ) t}{14}} + c_{2} e^{\frac{( - 1 - 29 ) t}{14}}

Solution steps

7 y^{''} (t) + y^{'} (t) - y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 1 + 29 ) t}{14}} + c_{2} e^{\frac{( - 1 - 29 ) t}{14}}

y = c_{1} e^{\frac{( - 1 + 29 ) t}{14}} + c_{2} e^{\frac{( - 1 - 29 ) t}{14}}

6 y^{^{''}} - 7 y^{^{'}} - 20 y = 0

y^{^{''''}} + 49 y^{^{''}} = 0

y^{^{''''}} - 8 y^{^{'''}} + 23 y^{^{''}} - 28 y^{^{'}} + 12 y = 0

a (4 y^{^{''}} + y^{^{'}}) + 4 y^{^{'}} + y = 0

u^{^{'''}} + 3 u^{^{''}} - 2 H (t) = 0

What is the solution for 7y^{''}+y^'-y=0 ?
The solution for 7y^{''}+y^'-y=0 is y=c_{1}e^{((-1+sqrt(29))t)/(14)}+c_{2}e^{((-1-sqrt(29))t)/(14)}