What is the integral of 1/(x^2e^{1/x)} ?

The integral of 1/(x^2e^{1/x)} is 1/(e^{1/x)}+C

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integral of 1/(x^2e^{1/x)}

\int \frac{1}{x ^{2} e ^{\frac{1}{x}}} d x

\frac{1}{e ^{\frac{1}{x}}} + C

Solution steps

\int \frac{1}{x ^{2} e ^{\frac{1}{x}}} d x

Apply u-substitution

: \int - \frac{1}{e ^{u}} d u

= \int - \frac{1}{e ^{u}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{e ^{u}} d u

Apply u-substitution

: \int \frac{1}{v ^{2}} d v

= - \int \frac{1}{v ^{2}} d v

Apply the Power Rule

: - \frac{1}{v}

= - (- \frac{1}{v})

Substitute back

= - (- \frac{1}{e ^{\frac{1}{x}}})

Simplify

= \frac{1}{e ^{\frac{1}{x}}}

Add a constant to the solution

= \frac{1}{e ^{\frac{1}{x}}} + C

\int (5 x - 1) (3 x^{2} + 2) d x

\int e^{x^{3}} (12 x^{2}) d x

\frac{\partial}{\partial x} (x e^{- \frac{y}{x}})

f (t) = \frac{3}{5} e^{- t} - \frac{22}{5} e^{4 t}

\int (\frac{3}{x ^{2}} - 1) d x

What is the integral of 1/(x^2e^{1/x)} ?
The integral of 1/(x^2e^{1/x)} is 1/(e^{1/x)}+C