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Popular >

8y^{''}+128y=0

Solution

8 y^{^{''}} + 128 y = 0

Solution

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Solution steps

8 y^{''} (t) + 128 y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Graph

Popular Examples

y^{''}+2y^'+35y=0,y(0)=-3,y^'(0)=1

y^{^{''}} + 2 y^{^{'}} + 35 y = 0, y (0) = - 3, y^{^{'}} (0) = 1

y^{'''}-4y^{''}-11y^'+30y=0

y^{^{'''}} - 4 y^{^{''}} - 11 y^{^{'}} + 30 y = 0

4(d^2y)/(dx^2)-100(dy)/(dx)-0.01y=0

4 \frac{d ^{2} y}{d x ^{2}} - 100 \frac{d y}{d x} - 0.01 y = 0

(D^2-D-2)(D^2-4D+6)y=0

(D^{2} - D - 2) (D^{2} - 4 D + 6) y = 0

4y^{''}-y=0,y(-2)=1,y(-2)=-1

4 y^{^{''}} - y = 0, y (- 2) = 1, y (- 2) = - 1

Frequently Asked Questions (FAQ)

What is the solution for 8y^{''}+128y=0 ?
The solution for 8y^{''}+128y=0 is y=c_{1}cos(4t)+c_{2}sin(4t)