What is the solution for y^{'''}-18y^{''}+89y^'-132y=0 ?

The solution for y^{'''}-18y^{''}+89y^'-132y=0 is y=c_{1}e^{3t}+c_{2}e^{4t}+c_{3}e^{11t}

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y^{'''}-18y^{''}+89y^'-132y=0

y^{^{'''}} - 18 y^{^{''}} + 89 y^{^{'}} - 132 y = 0

y = c_{1} e^{3 t} + c_{2} e^{4 t} + c_{3} e^{11 t}

Solution steps

y^{'''} (t) - 18 y^{''} (t) + 89 y^{'} (t) - 132 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{4 t} + c_{3} e^{11 t}

y = c_{1} e^{3 t} + c_{2} e^{4 t} + c_{3} e^{11 t}

y^{^{''}} + 0.75 y^{^{'}} + 0.3 y = 0, y^{^{'}} (0) = 0

16 y^{^{''}} - 24 y^{^{'}} + 9 y = 0, y^{1} (0) = e^{\frac{3 x}{4}}

400 y^{^{''}} - 9 y = 0

8 y^{^{''}} + 2 y = 0

\frac{1}{4} y^{^{''}} + y^{^{'}} + y = 0

What is the solution for y^{'''}-18y^{''}+89y^'-132y=0 ?
The solution for y^{'''}-18y^{''}+89y^'-132y=0 is y=c_{1}e^{3t}+c_{2}e^{4t}+c_{3}e^{11t}