What is the solution for (d^2y)/(dx^2)-2(dy)/(dx)+17y=0 ?

The solution for (d^2y)/(dx^2)-2(dy)/(dx)+17y=0 is y=e^x(c_{1}cos(4x)+c_{2}sin(4x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-2(dy)/(dx)+17y=0

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 17 y = 0

y = e^{x} (c_{1} cos (4 x) + c_{2} sin (4 x))

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 17 y = 0

Solve linear ODE:

y = e^{x} (c_{1} cos (4 x) + c_{2} sin (4 x))

y = e^{x} (c_{1} cos (4 x) + c_{2} sin (4 x))

y^{^{''}} - 7 y^{^{'}} + 10 y = 0, y (0) = 4, y^{^{'}} (0) = 17

y^{^{''}} - y^{^{'}} = y

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 5

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y^{^{'}} (0) = 8

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 0, y^{^{'}} (1) = 0

What is the solution for (d^2y)/(dx^2)-2(dy)/(dx)+17y=0 ?
The solution for (d^2y)/(dx^2)-2(dy)/(dx)+17y=0 is y=e^x(c_{1}cos(4x)+c_{2}sin(4x))