What is the limit as z approaches 2 of sqrt(7z^2+14z-7) ?

The limit as z approaches 2 of sqrt(7z^2+14z-7) is 7

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limit as z approaches 2 of sqrt(7z^2+14z-7)

z \to 2 lim (7 z^{2} + 14 z - 7)

7

Solution steps

z \to 2 lim (7 z^{2} + 14 z - 7)

Plug in the value

z = 2

= 7 \cdot 2^{2} + 14 \cdot 2 - 7

Simplify

7 \cdot 2^{2} + 14 \cdot 2 - 7 : 7

= 7

\int \frac{1}{( x ^{2} + 3 x - 4 )} d x

y = (3 x^{2} + 2) (4 x - 3)

\frac{5}{s - 3} - \frac{4}{s + 6}

\frac{d}{d x} (\frac{2 x + 1}{3 - x})

\frac{1}{s ^{2} ( s + 1 )}

What is the limit as z approaches 2 of sqrt(7z^2+14z-7) ?
The limit as z approaches 2 of sqrt(7z^2+14z-7) is 7