What is the solution for y^{''}+13y^'=0,y(0)=-9,y^'(0)=13 ?

The solution for y^{''}+13y^'=0,y(0)=-9,y^'(0)=13 is y=-e^{-13t}-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+13y^'=0,y(0)=-9,y^'(0)=13

y^{^{''}} + 13 y^{^{'}} = 0, y (0) = - 9, y^{^{'}} (0) = 13

y = - e^{- 13 t} - 8

Solution steps

y^{''} (t) + 13 y^{'} (t) = 0

Solve linear ODE:

y = - e^{- 13 t} - 8

y = - e^{- 13 t} - 8

49 y^{^{''}} - 168 y^{^{'}} + 144 y = 0

(D^{3} - 8) y = 0

\frac{5}{8} x^{^{''}} + 40 x = 0, x (0) = \frac{1}{4}, x^{^{'}} (0) = 0

y^{^{''}} + 6 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = - 6

y^{^{''}} + 6 y^{^{'}} + 25 y = 0, y (0) = 0, y^{^{'}} (0) = 2

What is the solution for y^{''}+13y^'=0,y(0)=-9,y^'(0)=13 ?
The solution for y^{''}+13y^'=0,y(0)=-9,y^'(0)=13 is y=-e^{-13t}-8