What is the derivative of ln(1-2x) ?

The derivative of ln(1-2x) is -2/(1-2x)

What is the first derivative of ln(1-2x) ?

The first derivative of ln(1-2x) is -2/(1-2x)

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\frac{d}{d x} (ln (1 - 2 x))

- \frac{2}{1 - 2 x}

Solution steps

\frac{d}{d x} (ln (1 - 2 x))

Apply the chain rule:

\frac{1}{1 - 2 x} \frac{d}{d x} (1 - 2 x)

= \frac{1}{1 - 2 x} \frac{d}{d x} (1 - 2 x)

\frac{d}{d x} (1 - 2 x) = - 2

= \frac{1}{1 - 2 x} (- 2)

Simplify

\frac{1}{1 - 2 x} (- 2) : - \frac{2}{1 - 2 x}

= - \frac{2}{1 - 2 x}

\frac{\partial}{\partial θ} (- e^{- 3 r} sin (θ))

x \to \infty lim (10)

\int \frac{1}{5} - \frac{6}{x} d x

n = 1 \sum \infty \frac{n !}{10 6 ^{n}}

\frac{d}{d t} (e^{3 t s i n (2 t)})

What is the derivative of ln(1-2x) ?
The derivative of ln(1-2x) is -2/(1-2x)
What is the first derivative of ln(1-2x) ?
The first derivative of ln(1-2x) is -2/(1-2x)