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Popular >

y^'-y^{''}=0

Solution

y^{^{'}} - y^{^{''}} = 0

Solution

y = c_{1} + c_{2} e^{t}

Solution steps

y^{'} (t) - y^{''} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{t}

y = c_{1} + c_{2} e^{t}

Popular Examples

x^{''}+2x^'+6x=0

x^{^{''}} + 2 x^{^{'}} + 6 x = 0

y^{''''}+20y^{''}-100y=0

y^{^{''''}} + 20 y^{^{''}} - 100 y = 0

y^{''}-3y^'+7y=0

y^{^{''}} - 3 y^{^{'}} + 7 y = 0

y^{'''}-5y^{''}+17y-13y=0

y^{^{'''}} - 5 y^{^{''}} + 17 y - 13 y = 0

(d^2f)/(dx^2)=af(x)

\frac{d ^{2} f}{d x ^{2}} = a f (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'-y^{''}=0 ?
The solution for y^'-y^{''}=0 is y=c_{1}+c_{2}e^t