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Popular >

y^{''}=2y^'-y

Solution

y^{^{''}} = 2 y^{^{'}} - y

Solution

y = c_{1} e^{t} + c_{2} t e^{t}

Solution steps

y^{''} (t) = 2 y^{'} (t) - y

Solve linear ODE:

y = c_{1} e^{t} + c_{2} t e^{t}

y = c_{1} e^{t} + c_{2} t e^{t}

Graph

Popular Examples

5 y^{^{''}} - 15 y = 0

y^{''}+8y^'+210y=0,y(0)=-1,y^'(0)=0

y^{^{''}} + 8 y^{^{'}} + 210 y = 0, y (0) = - 1, y^{^{'}} (0) = 0

((d^2y)/(dx^2)-2(dy)/(dx)+5y)^3=0

(\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 5 y)^{3} = 0

y^{''}-11y^'-24y=0

y^{^{''}} - 11 y^{^{'}} - 24 y = 0

x^{''''}+2x^{''}+x=0

x^{^{''''}} + 2 x^{^{''}} + x = 0

Frequently Asked Questions (FAQ)

What is the solution for y^{''}=2y^'-y ?
The solution for y^{''}=2y^'-y is y=c_{1}e^t+c_{2}te^t