What is the solution for y^{''}-7y^'-8y=0,y(0)=5,y^'(0)=-5 ?

The solution for y^{''}-7y^'-8y=0,y(0)=5,y^'(0)=-5 is y=5e^{-t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-7y^'-8y=0,y(0)=5,y^'(0)=-5

y^{^{''}} - 7 y^{^{'}} - 8 y = 0, y (0) = 5, y^{^{'}} (0) = - 5

y = 5 e^{- t}

Solution steps

y^{''} (t) - 7 y^{'} (t) - 8 y = 0

Solve linear ODE:

y = 5 e^{- t}

y = 5 e^{- t}

y^{^{'''''}} - 2 y^{^{'''}} - 2 y^{^{''}} - 3 y^{^{'}} - 2 y = 0

\frac{d ^{2} y}{d t ^{2}} - 6 \frac{d y}{d t} = 0

y^{^{'''}} + 7 y^{^{'}} = 0

x^{^{''}} = b x

y^{^{''}} + \frac{16}{3} y^{^{'}} + a y = 0, y (0) = 1, y^{^{'}} (0) = - \frac{4}{3}

What is the solution for y^{''}-7y^'-8y=0,y(0)=5,y^'(0)=-5 ?
The solution for y^{''}-7y^'-8y=0,y(0)=5,y^'(0)=-5 is y=5e^{-t}