What is the integral of (7/(x^4)) ?

The integral of (7/(x^4)) is -7/(3x^3)+C

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integral of (7/(x^4))

\int (\frac{7}{x ^{4}}) d x

- \frac{7}{3 x ^{3}} + C

Solution steps

\int \frac{7}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{x ^{4}} d x

Apply the Power Rule

: - \frac{1}{3 x ^{3}}

= 7 (- \frac{1}{3 x ^{3}})

Simplify

7 (- \frac{1}{3 x ^{3}}) : - \frac{7}{3 x ^{3}}

= - \frac{7}{3 x ^{3}}

Add a constant to the solution

= - \frac{7}{3 x ^{3}} + C

\frac{\partial}{\partial x} (ln (e^{x} + y))

\int \frac{x + 1}{( x - 3 ) ^{2}} d x

\int_{t}^{1} \frac{1}{x ^{2}} d x

x \to 8 lim (cos (\frac{π x}{3}))

y = \frac{x ^{4}}{f ( x )}