What is the solution for y^{''}+2y^'+2y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+2y^'+2y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}+2y^'+2y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 2 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + 2 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = 0

y = 0

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} + 5 y = 0

x^{^{''}} + c x = 0

y^{^{''}} - 2 y^{^{'}} = 0, y (0) = 1, y (1) = 0

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} + 10 y = 0

y^{^{''}} + 13 y^{^{''}} + 42 y = 0

What is the solution for y^{''}+2y^'+2y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+2y^'+2y=0,y(0)=0,y^'(0)=0 is y=0