What is the solution for y^{''}+4y^'+40y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+4y^'+40y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}+4y^'+40y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 4 y^{^{'}} + 40 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + 4 y^{'} (t) + 40 y = 0

Solve linear ODE:

y = 0

y = 0

x^{^{''}} - 0.5 x = 0

y^{^{''}} + 36 y = 0, y (0) = - 5, y^{^{'}} (0) = 12

y^{^{'''''}} - 16 y^{^{'}} = 0

0.2 y^{^{''}} + 5 y^{^{'}} + 500 y = 0, y (0) = 1, y^{^{'}} (0) = 0

x^{^{''}} - 10 x^{^{'}} + 29 x = 0

What is the solution for y^{''}+4y^'+40y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+4y^'+40y=0,y(0)=0,y^'(0)=0 is y=0