What is the solution for y^{''}-16y^'+113y=0 ?

The solution for y^{''}-16y^'+113y=0 is y=e^{8t}(c_{1}cos(7t)+c_{2}sin(7t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-16y^'+113y=0

y^{^{''}} - 16 y^{^{'}} + 113 y = 0

y = e^{8 t} (c_{1} cos (7 t) + c_{2} sin (7 t))

Solution steps

y^{''} (t) - 16 y^{'} (t) + 113 y = 0

Solve linear ODE:

y = e^{8 t} (c_{1} cos (7 t) + c_{2} sin (7 t))

y = e^{8 t} (c_{1} cos (7 t) + c_{2} sin (7 t))

y^{^{'''}} - 9 y^{^{''}} + 8 y^{^{'}} = 0

\frac{d ^{4} x}{d t ^{4}} - x = 0

y^{^{''}} + 2 y^{^{'}} + 17 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} - 5 y^{^{'}} - 6 y = 0, y (0) = a, y^{^{'}} (0) = 4

y^{^{''''}} - 44 y^{^{'''}} + 484 y^{^{''}} = 0

What is the solution for y^{''}-16y^'+113y=0 ?
The solution for y^{''}-16y^'+113y=0 is y=e^{8t}(c_{1}cos(7t)+c_{2}sin(7t))