What is the integral from 0 to 1 of 5^x ?

The integral from 0 to 1 of 5^x is 4/(ln(5))

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integral from 0 to 1 of 5^x

\int_{0}^{1} 5^{x} d x

\frac{4}{ln ( 5 )}

Decimal Notation

2.48533 \dots

Solution steps

\int_{0}^{1} 5^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{5 ^{x}}{ln ( 5 )}]_{0}^{1}

Compute the boundaries:

\frac{4}{ln ( 5 )}

= \frac{4}{ln ( 5 )}

sin (6 x)

y = \frac{1}{( t ^{4} + 1 ) ^{3}}

\frac{\partial}{\partial y} (\frac{2 x ^{2} y}{2 + x ^{2} y ^{2}})

n = 0 \sum \infty \frac{1}{ln ( n + 2 )}

\int \frac{x}{3 x ^{2} + 4} d x

What is the integral from 0 to 1 of 5^x ?
The integral from 0 to 1 of 5^x is 4/(ln(5))