What is the solution for y^{''}+9y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+9y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}+9y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 9 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + 9 y = 0

Solve linear ODE:

y = 0

y = 0

\frac{d ^{2} y}{d x ^{2}} - 9 \frac{d y}{d x} - 22 y = 0

\frac{d ^{2} y}{d x ^{2}} (1) - \frac{d y}{d x} (10) + 25 y = 0

y^{^{''}} + 64 y = 0, y (0) = 0, y^{^{'}} (0) = 8

0.5 \frac{d ^{2} y}{d x ^{2}} + 2 y = 0

12 y^{^{''}} - 12 y^{^{'}} + 150 y = 0

What is the solution for y^{''}+9y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+9y=0,y(0)=0,y^'(0)=0 is y=0