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Popular >

u^{''}+3u^'+5\H(t)=0

Solution

u^{''} + 3 u^{'} + 5 H (t (x)) = 0

Solution

0 + 3 \cdot 0 + 5 H (t (x)) = 0

Solution steps

u^{''} + 3 u^{'} + 5 H (t (x)) = 0

u^{''} = 0

0 + 3 u^{^{'}} + 5 H (t (x)) = 0

u^{'} = 0

0 + 3 \cdot 0 + 5 H (t (x)) = 0

Popular Examples

y^{''}-2y^'+2y=0,y(pi)=0,y(0)=0

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (π) = 0, y (0) = 0

y^{''}-10y^'+25y=0,y(0)=-1,y^'(0)=1

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = - 1, y^{^{'}} (0) = 1

4y^{''}+784y^'=0,y(0)=0

4 y^{^{''}} + 784 y^{^{'}} = 0, y (0) = 0

linear x^{''}-(a+3)x^'+2(a+1)x=0 linear

x^{^{''}} - (a + 3) x^{^{'}} + 2 (a + 1) x = 0

y^{''}+y^'=0,y(0)=1,y^'(0)=1

y^{^{''}} + y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

Frequently Asked Questions (FAQ)

What is u^{''}+3u^'+5\H(t)=0 ?
The answer to u^{''}+3u^'+5\H(t)=0 is 0+3*0+5\H(t(x))=0