What is the solution for y^{''}+14y^'+49y=0,y(0)=-1,y^'(0)=1 ?

The solution for y^{''}+14y^'+49y=0,y(0)=-1,y^'(0)=1 is y=-e^{-7t}-6e^{-7t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+14y^'+49y=0,y(0)=-1,y^'(0)=1

y^{^{''}} + 14 y^{^{'}} + 49 y = 0, y (0) = - 1, y^{^{'}} (0) = 1

y = - e^{- 7 t} - 6 e^{- 7 t} t

Solution steps

y^{''} (t) + 14 y^{'} (t) + 49 y = 0

Solve linear ODE:

y = - e^{- 7 t} - 6 e^{- 7 t} t

y = - e^{- 7 t} - 6 e^{- 7 t} t

y^{^{''''}} - 3 y^{^{'''}} - 4 y^{^{''}} = 0

y^{^{''}} - y^{^{'}} + 2 y = 0, y (0) = 2, y (2) = 1

2 y^{^{''}} - 2 y^{^{'}} + 4 y = 0

y^{^{''}} + 4 y^{^{'}} - 5 y = 0, y (0) = - 3, y^{^{'}} (0) = 21

y^{^{''}} + y = 0, y (π) = 1, y^{^{'}} (0) = 0

What is the solution for y^{''}+14y^'+49y=0,y(0)=-1,y^'(0)=1 ?
The solution for y^{''}+14y^'+49y=0,y(0)=-1,y^'(0)=1 is y=-e^{-7t}-6e^{-7t}t